64x^2=-32x

Solution for 64x^2=-32x equation:

64x^2=-32x

We move all terms to the left:

64x^2-(-32x)=0

We get rid of parentheses

64x^2+32x=0

a = 64; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·64·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*64}=\frac{-64}{128}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*64}=\frac{0}{128}
=0
$